To determine the octant in which the point (2, -4, -7) lies, we need to consider the signs of its coordinates.
In an octant, the x, y, and z coordinates can have either positive (+) or negative (-) values.
Given the point (2, -4, -7), we can determine the octant as follows:
First, consider the x-coordinate, which is 2. Since it is positive, we eliminate the octants with negative x-values (4th, 5th, 6th, and 7th).
Next, consider the y-coordinate, which is -4. Since it is negative, we eliminate the octants with positive y-values (1st, 2nd, 5th, and 6th).
Lastly, consider the z-coordinate, which is -7. Since it is negative, we eliminate the octants with positive z-values (1st, 2nd, 3rd, and 4th).
Based on the elimination process, we find that the point (2, -4, -7) lies in the Eighth octant.
Therefore, the octant in which the point (2, -4, -7) lies is the Eighth octant (option A).
The area of the quadrilateral having vertices as (1,2), (5,6), (7,6), (-1,-6) is?
The foot of perpendicular from the origin $O$ to a plane $P$ which meets the co-ordinate axes at the points $A , B , C$ is $(2, a , 4), a \in N$ If the volume of the tetrahedron $OABC$ is 144 unit $^3$, then which of the following points is NOT on $P$ ?