Eighth
To determine the octant in which the point (2, -4, -7) lies, we need to consider the signs of its coordinates.
In an octant, the x, y, and z coordinates can have either positive (+) or negative (-) values.
Given the point (2, -4, -7), we can determine the octant as follows:
First, consider the x-coordinate, which is 2. Since it is positive, we eliminate the octants with negative x-values (4th, 5th, 6th, and 7th).
Next, consider the y-coordinate, which is -4. Since it is negative, we eliminate the octants with positive y-values (1st, 2nd, 5th, and 6th).
Lastly, consider the z-coordinate, which is -7. Since it is negative, we eliminate the octants with positive z-values (1st, 2nd, 3rd, and 4th).
Based on the elimination process, we find that the point (2, -4, -7) lies in the Eighth octant.
Therefore, the octant in which the point (2, -4, -7) lies is the Eighth octant (option A).
The point is (2, -4, -7)
→ x > 0, y < 0, z < 0
In 3D geometry, space is divided into **8 octants** based on the signs of x, y, and z:
So, the point (2, -4, -7) lies in the Eighth octant.
Correct answer: Eighth
The octants in 3D space are defined by the signs of the x, y, and z coordinates.
The signs for each octant are as follows:
The point (2, -4, -7) has signs (+, -, -). Comparing this to the table, we see that it corresponds to Octant VIII (Eighth Octant).
Therefore, the octant in which the point (2, -4, -7) lies is the Eighth octant.
Answer: Eighth
The foot of perpendicular from the origin $O$ to a plane $P$ which meets the co-ordinate axes at the points $A , B , C$ is $(2, a , 4), a \in N$ If the volume of the tetrahedron $OABC$ is 144 unit $^3$, then which of the following points is NOT on $P$ ?