Step 1: Count the total number of letters in the word "DEPENDENT". The word has 9 letters: D, E, P, E, N, D, E, N, T.
Step 2: Count the frequency of each distinct letter. - D appears 2 times - E appears 3 times - P appears 1 time - N appears 2 times - T appears 1 time Total letters \( n = 9 \).
Step 3: Apply the formula for permutations with repetitions. The number of distinct permutations of \( n \) objects where there are \( n_1 \) identical objects of type 1, \( n_2 \) identical objects of type 2, ..., \( n_k \) identical objects of type k is given by: \[ \frac{n!}{n_1! n_2! \cdots n_k!} \] In this case, \( n = 9 \), and the counts of repeated letters are \( n_D = 2 \), \( n_E = 3 \), \( n_N = 2 \).
Step 4: Substitute the values into the formula. \[ \text{Number of permutations} = \frac{9!}{2! \times 3! \times 2!} \]
Step 5: Calculate the factorial values and the final result. \[ 9! = 362,880 \] \[ 2! = 2 \] \[ 3! = 6 \] \[ 2! = 2 \] \[ \text{Number of permutations} = \frac{362,880}{2 \times 6 \times 2} = \frac{362,880}{24} \] \[ \text{Number of permutations} = 15,120 \]
Step 6: Compare the result with the given options. The calculated number of permutations is 15,120, which matches option (A).
The number of strictly increasing functions \(f\) from the set \(\{1, 2, 3, 4, 5, 6\}\) to the set \(\{1, 2, 3, ...., 9\}\) such that \(f(i)>i\) for \(1 \le i \le 6\), is equal to: