Question:
The number of moles of electron required to reduce 0.2 mole of Cr2O-27 to Cr+3
The number of moles of electron required to reduce 0.2 mole of Cr2O-27 to Cr+3
Updated On: Feb 23, 2024
- 12
- 0.6
- 1.2
- 6
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The Correct Option is C
Solution and Explanation
$Cr_{2}^{+6}O_{7}^{2-} $ ${ ->[6e^{-}] }$ $2 Cr^{+3}$
1 mol requires 6 mole of electrons
0.2 mol requires $\frac{0.2\times6}{1}=1.2 \,$ mol of electrons
1 mol requires 6 mole of electrons
0.2 mol requires $\frac{0.2\times6}{1}=1.2 \,$ mol of electrons
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Concepts Used:
Oxidation and Reduction
What is Oxidation?
Oxidation is a chemical process which can be explained by following four point of views
In terms of oxygen transfer
In terms of electron transfer
In terms of hydrogen transfer
In terms of oxidation number
Oxidation in Terms of Oxygen Transfer – Oxidation is gain of oxygen.
What is Reduction?
Reduction is a chemical process which can be explained by following four point of views
In terms of oxygen transfer
In terms of electron transfer
In terms of hydrogen transfer
In terms of oxidation number
Reduction in Terms of Oxygen Transfer – Reduction is loss of oxygen.
What is Redox Reaction?
A chemical reaction which involves transfer of electrons or change in oxidation number of atoms is called redox reaction.