Step 1: Reaction: $PCl_3 + 3H_3PO_3 \rightarrow$ The product is Pyrophosphorous acid ($H_4P_2O_5$).
Step 2: The structure of $H_4P_2O_5$ contains two P atoms connected by an O bridge (P-O-P). Each P is bonded to one H and one OH group.
Step 3: Only Hydrogens attached to Oxygen ($P-OH$) are ionisable.
Step 4: There are 2 such $OH$ groups, so 2 ionisable hydrogens.