9
32
We are given the principal quantum number n = 3 and spin quantum number ms = +1/2.
For n = 3, the possible values of the azimuthal quantum number l are:
Each subshell has the following number of orbitals:
Total orbitals for n = 3: 1 + 3 + 5 = 9
Each orbital can hold 2 electrons, one with spin +1/2 and one with spin -1/2.
So, the number of electrons with ms = +1/2 will be:
9 orbitals × 1 electron per orbital = 9 electrons
Correct Answer: (A) 9
List I | List II | ||
A. | \(∇^2\psi+\frac{8\pi^2m}{h^2}(E-V)\psi=0\) | I. | Planck |
B. | \(E=hv\) | II. | Heisenberg |
C. | \(\Delta x.\Delta p≥\frac{h}{4\pi}\) | III. | Schrodinger |
D. | \(\lambda=\frac{h}{p}\) | IV. | de Broglie |