Step 1: Formula for \(k\)-cycles.
In \(S_n\), the number of distinct \(k\)-cycles is given by
\[
\frac{1}{k} \binom{n}{k} (k-1)! = \frac{n!}{k(n-k)! \, k!} = \frac{n!}{k \, (n-k)! \, k}.
\]
Simplifying, we use:
\[
\text{Number of } k\text{-cycles in } S_n = \frac{n!}{(n-k)! \, k}.
\]
Step 2: Apply for \(n=6, k=4.\)
\[
\text{Number} = \frac{6!}{(6-4)! \times 4} = \frac{720}{2! \times 4} = \frac{720}{8} = 90.
\]
Step 3: Conclusion.
Hence, the number of 4-cycles in \(S_6\) is \(\boxed{90}.\)