Four elements overall are contained in a \(2 × 2\) matrix.
Either \(1\) or \(0\) can be used in place of each element.
Each of the four spaces can therefore be filled in one of two ways.
Therefore, there will be a total of \(2×2×2×2 = 2^4\) matrices in this type of matrix.
Consequently, \(16\) is the maximum number of \(2\times2\) order matrices that can have either \(0\) or \(1\) for each entry.
An amount of ₹ 10,000 is put into three investments at the rate of 10%, 12% and 15% per annum. The combined annual income of all three investments is ₹ 1,310, however, the combined annual income of the first and second investments is ₹ 190 short of the income from the third. Use matrix method and find the investment amount in each at the beginning of the year.
If \[ A = \begin{bmatrix} 1 & 2 & 0 \\ -2 & -1 & -2 \\ 0 & -1 & 1 \end{bmatrix} \] then find \( A^{-1} \). Hence, solve the system of linear equations: \[ x - 2y = 10, \] \[ 2x - y - z = 8, \] \[ -2y + z = 7. \]
Match List I with List II:
Choose the correct answer from the options given below:
A matrix is a rectangular array of numbers, variables, symbols, or expressions that are defined for the operations like subtraction, addition, and multiplications. The size of a matrix is determined by the number of rows and columns in the matrix.