Question:

The Newton-Raphson method is applied to determine the solution of \( f(x) = 0 \) where \( f(x) = x - \cos(x) \). If the initial guess of the solution is \( x_0 = 0 \), the value of the next approximation \( x_1 \) is _________ (round off to two decimal places).

Updated On: Nov 25, 2025
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Correct Answer: 0.99

Solution and Explanation

The Newton-Raphson method is given by the formula: \[ x_{n+1} = x_n - \frac{f(x_n)}{f'(x_n)} \] We are given \( f(x) = x - \cos(x) \), so: \[ f'(x) = 1 + \sin(x) \] At \( x_0 = 0 \): \[ f(0) = 0 - \cos(0) = -1, \quad f'(0) = 1 + \sin(0) = 1 \] Now, using the Newton-Raphson formula to find \( x_1 \): \[ x_1 = 0 - \frac{-1}{1} = 1 \] Thus, the next approximation is \( x_1 = 1.0 \).
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