Question:

The monosaccharides of maltose is

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Remember: Maltose = \( \alpha \)-D-glucose + \( \alpha \)-D-glucose via \( \alpha(1 \rightarrow 4) \) linkage.
Updated On: Apr 15, 2025
  • \( \alpha \)-D-glucose and \( \alpha \)-D-glucose
  • \( \beta \)-D-glucose and \( \alpha \)-D-glucose
  • \( \alpha \)-D-glucose and \( \alpha \)-D-fructose
  • \( \alpha \)-D-glucose and \( \beta \)-D-fructose
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The Correct Option is A

Solution and Explanation


Step 1: Maltose is a disaccharide formed from two units of glucose joined by an \( \alpha(1 \rightarrow 4) \) glycosidic bond.
Step 2: When maltose undergoes hydrolysis (with acid or enzyme like maltase), it yields two molecules of glucose. Both glucose molecules in maltose are typically in the \( \alpha \)-form.
Step 3: The reducing end of maltose has a free hemiacetal group from one \( \alpha \)-D-glucose molecule, while the other is involved in the glycosidic linkage.
Therefore, the monosaccharides formed are two \( \alpha \)-D-glucose molecules.
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