Question

The molar solubility of PbI₂ in 0.2 M Pb(NO₃)₂ solution in terms of \(K_{sp}\) (solubility product) is

• A. \( K_{sp}^{1/2} \, 0.2 \)
• B. \( K_{sp}^{1/2} \, 0.8 \)
• C. \( K_{sp}^{1/4} \, 0.4 \)
• D. \( K_{sp}^{1/3} \, 0.8 \)

Hint:

When dealing with solubility equilibria, remember to adjust the solubility expression for the concentration of common ions in the solution.

Answer 1

The Correct Option is C

The molar solubility of a sparingly soluble salt like PbI₂ is related to the solubility product constant \( K_{sp} \) and the concentration of common ions in solution. The relationship involves raising \( K_{sp} \) to the appropriate power, and the correct formula for this scenario is \( K_{sp}^{1/4} \, 0.4 \).