Step 1: Recall the formula for the \( n \)-th term of an AP.
The \( n \)-th term of an AP is given by:
\[ a_n = a + (n - 1)d, \]
where \( a \) is the first term and \( d \) is the common difference.
Step 2: Identify known terms and find the common difference \( d \).
The first term \( a = 3 \). The third term is \( a_3 = 33 \), and the fourth term is \( a_4 = 48 \).
Using the formula for the \( n \)-th term:
\[ a_3 = a + 2d \quad \text{and} \quad a_4 = a + 3d. \]
Substitute \( a_3 = 33 \) and \( a = 3 \):
\[ 33 = 3 + 2d \implies 2d = 30 \implies d = 15. \]
Step 3: Find the second term (\( a_2 \)).
The second term is given by:
\[ a_2 = a + d = 3 + 15 = 18. \]
Final Answer: The missing term is \( \mathbf{18} \).
Consider an A.P. $a_1,a_2,\ldots,a_n$; $a_1>0$. If $a_2-a_1=-\dfrac{3}{4}$, $a_n=\dfrac{1}{4}a_1$, and \[ \sum_{i=1}^{n} a_i=\frac{525}{2}, \] then $\sum_{i=1}^{17} a_i$ is equal to