For efficient transmission and reception of electromagnetic waves, the size of the antenna should generally be comparable to the wavelength ($\lambda$) of the waves being transmitted or received. A common rule of thumb for a minimum or practical size, especially for a simple dipole antenna, is that its length should be of the order of $\lambda/4$ or $\lambda/2$. The question asks for the "minimum size," which often relates to $\lambda/4$.
First, calculate the wavelength ($\lambda$) of the electromagnetic waves.
The relationship between wavelength ($\lambda$), frequency ($f$), and the speed of light ($c$) is $c = f\lambda$.
So, $\lambda = \frac{c}{f}$.
Given values:
Frequency $f = 1500 \text{ MHz} = 1500 \times 10^6 \text{ Hz} = 1.5 \times 10^9 \text{ Hz}$.
Speed of light $c = 3 \times 10^8 \text{ m/s}$.
Calculate $\lambda$:
$\lambda = \frac{3 \times 10^8 \text{ m/s}}{1.5 \times 10^9 \text{ Hz}} = \frac{3}{1.5} \times \frac{10^8}{10^9} \text{ m}$.
$\frac{3}{1.5} = 2$.
$\frac{10^8}{10^9} = 10^{-1} = 0.1$.
So, $\lambda = 2 \times 0.1 \text{ m} = 0.2 \text{ m}$.
Convert wavelength to centimeters:
$\lambda = 0.2 \text{ m} \times 100 \frac{\text{cm}}{\text{m}} = 20 \text{ cm}$.
Now, consider the minimum size of the antenna. A common practical minimum length for an efficient antenna (like a quarter-wave monopole or one arm of a half-wave dipole) is $\lambda/4$.
Minimum size $\approx \frac{\lambda}{4}$.
Minimum size $\approx \frac{20 \text{ cm}}{4} = 5 \text{ cm}$.
This matches option (b).
If the antenna were a half-wave dipole, its total length would be $\lambda/2 = 20 \text{ cm}/2 = 10 \text{ cm}$.
The term "size" could refer to the characteristic dimension. For many antenna types, $\lambda/4$ is a key dimension.
Given the options, 5 cm is a strong candidate.
\[ \boxed{5 \text{ cm}} \]