Question:

The mean of 5 observations is \(\frac {24}{5}\) and variance is \(\frac {194}{25}\) . If the mean of first four observations is \(\frac 72\) , then the variance of first four observations is

Updated On: Jun 2, 2024
  • \(\frac 32\)

  • \(\frac 52\)

  • \(\frac 54\)

  • \(\frac 23\)

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The Correct Option is C

Solution and Explanation

The correct option is (C): \(\frac 54\).

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Questions Asked in JEE Main exam

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Concepts Used:

Variance and Standard Deviation

Variance:

According to layman’s words, the variance is a measure of how far a set of data are dispersed out from their mean or average value. It is denoted as ‘σ2’.

Variance Formula:

Read More: Difference Between Variance and Standard Deviation

Standard Deviation:

The spread of statistical data is measured by the standard deviation. Distribution measures the deviation of data from its mean or average position. The degree of dispersion is computed by the method of estimating the deviation of data points. It is denoted by the symbol, ‘σ’.

Types of Standard Deviation:

  • Standard Deviation for Discrete Frequency distribution
  • Standard Deviation for Continuous Frequency distribution

Standard Deviation Formulas:

1. Population Standard Deviation

2. Sample Standard Deviation