Question:

The maximum value of \( x + y \) subject to \[ 2x + 3y \leq 6, \quad x \geq 0, \quad y \geq 0 \] is:

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Always graph the inequality constraints and evaluate at the feasible points to find the maximum or minimum value.
Updated On: Apr 23, 2025
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The Correct Option is D

Solution and Explanation

We are given the following constraints: \[ 2x + 3y \leq 6, \quad x \geq 0, \quad y \geq 0 \] First, plot the constraint line \( 2x + 3y = 6 \) and find the feasible region. We also need to maximize \( x + y \). The intersection of \( 2x + 3y = 6 \) with the axes is at:
- \( x = 3, y = 0 \) for the x-intercept.
- \( x = 0, y = 2 \) for the y-intercept. By evaluating at different points in the feasible region, we can see that the maximum value of \( x + y \) occurs at \( x = 1, y = 2 \), giving a value of \( x + y = 3 \). Thus, the maximum value is 3.
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