Question

The maximum speed in \(\mu\text{m/s}\) at which the \(8^\text{th}\) bright fringe will move is .

Hint:

For oscillatory motion, maximum speed is given by the product of the angular frequency and the amplitude.

Answer 1

The amplitude of oscillation of the fringe is: \[ A = \frac{\Delta y}{2} = \frac{601.50}{2} = 300.75 \, \mu\text{m}. \] The maximum speed is given by: \[ v_{\text{max}} = A \omega. \] Substitute: \[ v_{\text{max}} = 300.75 \cdot 0.08 = 24 \, \mu\text{m/s}. \]