Question:

The maximum of the function \( f(x, y, z) = xyz \) subject to the constraints \[ xy + yz + zx = 12, \quad x>0, y>0, z>0, \] is equal to (round off to TWO decimal places):

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For constrained optimization, use symmetry and constraints to simplify calculations.
Updated On: Feb 1, 2025
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Solution and Explanation

Step 1: Applying Lagrange multipliers. Define the Lagrangian: \[ \mathcal{L}(x, y, z, \lambda) = xyz + \lambda(12 - xy - yz - zx). \] Step 2: Solving the system of equations. Taking partial derivatives and solving the resulting system yields the critical points. Substituting into the constraint: \[ x = y = z = 2. \] Step 3: Evaluating \( f(x, y, z) \). \[ f(2, 2, 2) = 2 \cdot 2 \cdot 2 = 8. \] Step 4: Conclusion. The maximum value is \( {8} \).
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