Question:

The maximum and minimum distance of a comet from the sun are $ 8\times 10^{12}m$ and $ 1.6\times 10^{12}m$ . If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when farthest?

Updated On: Jun 7, 2022
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The Correct Option is A

Solution and Explanation

According to law of conservation of angular momentum $ m{{\upsilon }_{1}}{{r}_{1}}=m{{\upsilon }_{2}}{{r}_{2}} $ or $ {{\upsilon }_{1}}=\frac{{{\upsilon }_{2}}{{r}_{2}}}{{{r}_{1}}} $ $ =\frac{60\times 1.6\times {{10}^{12}}}{8\times {{10}^{12}}}=12\,m\text{/}s $
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].