For a line-to-ground (LG) fault, the zero-sequence current is related to the current through the neutral. The total neutral current is generally 3 times the zero-sequence current. Since the zero-sequence current in this case is 2.4 p.u., the current through the neutral is:
\[
I_{\text{neutral}} = \frac{2.4}{3} = 0.8 \, \text{p.u.}
\]
Thus, the current through the neutral during the fault is 0.8 p.u., which corresponds to option (2).