Question:

The magnitude of zero sequence current of a generator for LG fault is 2.4 p.u. The current through the neutral during fault in p.u. is:

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For an LG fault, the current through the neutral is one-third of the zero-sequence current.
Updated On: May 4, 2025
  • 2.4
  • 0.8
  • 7.2
  • 0.24
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The Correct Option is B

Solution and Explanation

For a line-to-ground (LG) fault, the zero-sequence current is related to the current through the neutral. The total neutral current is generally 3 times the zero-sequence current. Since the zero-sequence current in this case is 2.4 p.u., the current through the neutral is:
\[ I_{\text{neutral}} = \frac{2.4}{3} = 0.8 \, \text{p.u.} \] Thus, the current through the neutral during the fault is 0.8 p.u., which corresponds to option (2).
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