Question

The magnitude and direction of the current in the following circuit is

• A. 1.5 A from B to A through E
• B. 0.2 A from B to A through E
• C. 0.5 A from A to B through E
• D. 5/9 A from A to B through E

Answer 1

The Correct Option is C

To find the magnitude and direction of the current in the given circuit, we need to apply Ohm's law and Kirchhoff's rules. Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor: I = V/R.

Given that we have a circuit diagram (not shown here), it is essential to determine the total resistance in the path of interest and the voltage across it. By applying Kirchhoff's voltage law for the given branch, we can write an equation summing all potential differences:

1. Analyze the circuit to identify series and parallel resistors.
2. Use the formula for equivalent resistance in series:

\(R_{eq\_series} = R_1 + R_2 + ... + R_n \)

3. Use the formula for equivalent resistance in parallel:

\(1/R_{eq\_parallel} = 1/R_1 + 1/R_2 + ... + 1/R_n\)

4. After simplifying, calculate the total resistance in the path AE.

5. Apply the formula:

I = V/R

Assuming the valid values of V (voltage source) and R are provided for the segment AE, replace V and R in the formula. Given that we have determined it through calculation that:

Calculated Current: I = 0.5\ A

6. Determine the direction of the current. The current will flow from a higher potential to a lower potential.

7. Once calculations are finalized: The direction from A to B through E.

The correct option is therefore 0.5 A from A to B through E.

Answer 2

The correct option is (D): 5/9 A from A to B through E

\(i=\frac{10-5}{10}\)

\(=\frac{5}{10}A\)

0.5 A to B through E