The logic performed by the circuit shown in the figure is equivalent to:
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Show Hint
De Morgan’s laws simplify logic circuits: \( \overline{A + B} = A \cdot B \) and \( \overline{A \cdot B} = A + B \). These transformations can turn complex circuits into simpler ones.
The circuit performs the following logical operations:
1. The first two NOT gates take inputs \( a \) and \( b \), producing the complements \( \bar{a} \) and \( \bar{b} \) respectively.
\[
\text{Output of the first NOT gate: } \bar{a}, \quad \text{Output of the second NOT gate: } \bar{b}.
\]
2. The OR gate then combines the complements:
\[
\text{Output of the OR gate: } \bar{a} + \bar{b}.
\]
3. The result from the OR gate is then complemented by another NOT gate, yielding the final output:
\[
Y = \overline{\bar{a} + \bar{b}}.
\]
Using De Morgan's law, we simplify:
\[
Y = a \cdot b.
\]
Thus, the circuit implements the logic of an AND gate.
Truth Table:
\[
\begin{array}{|c|c|c|}
\hline
A & B & Y = A \cdot B
\hline
0 & 0 & 0
0 & 1 & 0
1 & 0 & 0
1 & 1 & 1
\hline
\end{array}
\]
The output matches the truth table of an AND gate.
Final Answer:
\[
\boxed{\text{AND Gate}}
\]