Question

The logic circuit shown above is equivalent to : 

• A. A
• B. B
• C. C
• D. D

Hint:

Use De Morgan's Law: $\overline{A \cdot B} = \overline{A} + \overline{B}$ and $\overline{A + B} = \overline{A} \cdot \overline{B}$ to simplify any complex logic circuit quickly.

Answer 1

The Correct Option is C

Step 1: Analyze the standard configuration. If the circuit shows two inputs $A$ and $B$ going through an OR gate followed by a NOT gate (or a NAND where inputs are inverted), we apply De Morgan’s Laws.
Step 2: For example, if the diagram is $\overline{A+B}$, it is a NOR gate. If it is $\overline{A} \cdot \overline{B}$, it is also equivalent to a NOR gate.