Question:

The kinetic energy of a particle moving along a circle of radius $R$ is $K$. The force acting on the particle is

Updated On: Aug 1, 2022
  • $\frac{K}{R}$
  • $\frac{2K}{R}$
  • $\frac{K}{2R}$
  • $\frac{K}{R^2}$
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The Correct Option is B

Solution and Explanation

Kinetic energy of a particle, $K=\frac{1}{2}mv^{2}\quad...\left(i\right) $ where $m$ is the mass and $v$ be speed of the particle. Force acting on the particle is $F = \frac{mv^{2}}{R} $ $ F= \frac{2K}{R} $ (Using$(i)$)
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Concepts Used:

Kinetic energy

Kinetic energy of an object is the measure of the work it does as a result of its motion. Kinetic energy is the type of energy that an object or particle has as a result of its movement. When an object is subjected to a net force, it accelerates and gains kinetic energy as a result. Kinetic energy is a property of a moving object or particle defined by both its mass and its velocity. Any combination of motions is possible, including translation (moving along a route from one spot to another), rotation around an axis, vibration, and any combination of motions.