Question

The ionization energy of hydrogen in the ground state is

• A. \( 13.6 \, \text{eV} \)
• B. \( 27.2 \, \text{eV} \)
• C. \( 5.0 \, \text{eV} \)
• D. \( 18.0 \, \text{eV} \)

Hint:

The ionization energy of hydrogen in its ground state is always \( 13.6 \, \text{eV} \), which corresponds to the energy required to completely remove the electron from the atom.

Answer 1

The Correct Option is A

The ionization energy of hydrogen in the ground state is the energy required to remove the electron from the n = 1 level to the n = ∞ level. From Bohr's model, the ionization energy for hydrogen is given by: \[ E = \frac{13.6}{n^2} \, \text{eV}, \, \text{for} \, n = 1 \, \text{(ground state)} \quad \Rightarrow \quad E = 13.6 \, \text{eV}. \]