Step 1: Na⁺, Mg²⁺, and Al³⁺ are **isoelectronic species** (all have 10 electrons).
Step 2: For isoelectronic species, as the nuclear charge (atomic number $Z$) increases, the nucleus pulls electrons more strongly.
Step 3: $Z$ for Na=11, Mg=12, Al=13.
Step 4: Therefore, ionic radius decreases: Na⁺>Mg²⁺>Al³⁺.
The only option following this trend with values significantly smaller than 1.02 is (B).