Question:

The intercept cut off on the \(x\)-axis by the plane \(3x+4y+5z=13\) is

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To find the $x$-intercept of a plane, set $y=z=0$ and solve for $x$.
  • \(\dfrac{3}{13}\)
  • \(\dfrac{13}{3}\)
  • \(\dfrac{13}{4}\)
  • \(\dfrac{13}{5}\)
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The Correct Option is B

Solution and Explanation

On the \(x\)-axis \(y=z=0\). Substitute into the plane: \[ 3x=13\Rightarrow x=\frac{13}{3}. \] That is the \(x\)-intercept.
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