Question:
The integrating factor of the differential equation (1 +y2)dx - (tan-1 y - x)dy = 0, is :
The integrating factor of the differential equation (1 +y2)dx - (tan-1 y - x)dy = 0, is :
Updated On: Jun 13, 2024
- tan-1 y
- \(e^{\tan^{-1}y}\)
- \(\frac{1}{1+y^2}\)
- \(\frac{1}{x(1+y^2)}\)
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The Correct Option is B
Solution and Explanation
The correct option is (B) :\(e^{\tan^{-1}y}\).
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