The integrating factor of the differential equation \(x\frac{dy}{dx}-y=2x^{2}\) is
\(e-x\)
\(e-y\)
\(\frac{1}{x}\)
\(x\)
The given differential equation is:
\(x\frac{dy}{dx}-y=2x^{2}\)
\(⇒\frac{dy}{dx}-\frac{y}{x}=2x\)
This is a linear differential equation of the form:
\(\frac{dy}{dx}+py=Q\)\(=Q(where\) \(p=\)\(\frac{-1}{x}\) \(and\) \(Q=2x\)).
The integrating factor(I.F.)is given by the relation,
\(e^{∫pdx}\)
\(∴I.F.=\) \(e^{∫\frac{-1}{x}dx}\)=\(e^{-logx}\)=\(e^{log(x^{-1})}\)=\(x^{-1}\)=\(\frac{1}{x}\)
Hence,the correct answer is C.
परसेवा का आनंद — 120 शब्दों में रचनात्मक लेख लिखिए:
Answer the following questions:
[(i)] Explain the structure of a mature embryo sac of a typical flowering plant.
[(ii)] How is triple fusion achieved in these plants?
OR
[(i)] Describe the changes in the ovary and the uterus as induced by the changes in the level of pituitary and ovarian hormones during menstrual cycle in a human female.
A relation between involved variables, which satisfy the given differential equation is called its solution. The solution which contains as many arbitrary constants as the order of the differential equation is called the general solution and the solution free from arbitrary constants is called particular solution.
Read More: Formation of a Differential Equation