Step 1: The greatest integer function \( \left\lfloor x \right\rfloor \) gives the largest integer less than or equal to \( x \). The value of \( \left\lfloor x \right\rfloor \) changes at each integer value of \( x \).
Step 2: Break the integral into parts where \( \left\lfloor x \right\rfloor \) remains constant:
\[
\int_5^{10} \left\lfloor x \right\rfloor dx = \int_5^6 5 dx + \int_6^7 6 dx + \int_7^8 7 dx + \int_8^9 8 dx + \int_9^{10} 9 dx.
\]
Step 3: Now, calculate each integral:
\[
\int_5^6 5 dx = 5 \times (6 - 5) = 5,
\]
\[
\int_6^7 6 dx = 6 \times (7 - 6) = 6,
\]
\[
\int_7^8 7 dx = 7 \times (8 - 7) = 7,
\]
\[
\int_8^9 8 dx = 8 \times (9 - 8) = 8,
\]
\[
\int_9^{10} 9 dx = 9 \times (10 - 9) = 9.
\]
Step 4: Adding these values gives:
\[
5 + 6 + 7 + 8 + 9 = 35.
\]