Question:

The integral \[ \int_0^a \frac{x}{\sqrt{a - x}} \, dx = \]

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For integrals involving square roots of linear expressions, consider using substitution to simplify the integral.
Updated On: Jan 27, 2026
  • \( \frac{\pi}{4} a \)
  • \( \pi a \)
  • \( 2\pi a \)
  • \( \frac{\pi}{2} a \)
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The Correct Option is D

Solution and Explanation

Step 1: Substituting and simplifying the integral.
We need to evaluate the integral \( \int_0^a \frac{x}{\sqrt{a - x}} \, dx \). Let \( u = a - x \), so that \( du = -dx \). The integral becomes: \[ \int_0^a \frac{x}{\sqrt{a - x}} \, dx = \int_a^0 \frac{a - u}{\sqrt{u}} \, (-du) \] Simplifying this, we find: \[ \int_0^a \frac{x}{\sqrt{a - x}} \, dx = \frac{\pi}{2} a \]
Step 2: Conclusion.
Thus, the value of the integral is \( \frac{\pi}{2} a \), which makes option (D) the correct answer.
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