Question:

The integral $ \int_0^1 \frac{1}{2 + \sqrt{2e}} \, dx $ is:

Show Hint

For integrals involving constants, the solution is often as simple as multiplying the constant by the length of the integration interval.
Updated On: Apr 27, 2025
  • \( \frac{1}{2} \ln (2 + \sqrt{2e}) \)
  • \( \frac{1}{\sqrt{2}} \)
  • \( \frac{1}{\sqrt{2}} \ln (2 + \sqrt{2e}) \)
  • \( \frac{1}{2 \sqrt{2}} \)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

The given integral is: \[ \int_0^1 \frac{1}{2 + \sqrt{2e}} \, dae \] 
Since this is a straightforward integral with respect to \( a \), we can directly integrate the expression. The integration is relatively simple as the denominator is constant with respect to \( a \), so the result of the integral is: \[ \frac{1}{2\sqrt{2}} \] 
Thus, the correct answer is \( \frac{1}{2 \sqrt{2}} \).

Was this answer helpful?
0
0