The integral $ \int_0^1 \frac{1}{2 + \sqrt{2e}} \, dx $ is:
The given integral is: \[ \int_0^1 \frac{1}{2 + \sqrt{2e}} \, dae \]
Since this is a straightforward integral with respect to \( a \), we can directly integrate the expression. The integration is relatively simple as the denominator is constant with respect to \( a \), so the result of the integral is: \[ \frac{1}{2\sqrt{2}} \]
Thus, the correct answer is \( \frac{1}{2 \sqrt{2}} \).
Find the area of the region (in square units) enclosed by the curves: \[ y^2 = 8(x+2), \quad y^2 = 4(1-x) \] and the Y-axis.