The integral $ \int_0^1 \frac{1}{2 + \sqrt{2e}} \, dx $ is:
The given integral is: \[ \int_0^1 \frac{1}{2 + \sqrt{2e}} \, dae \]
Since this is a straightforward integral with respect to \( a \), we can directly integrate the expression. The integration is relatively simple as the denominator is constant with respect to \( a \), so the result of the integral is: \[ \frac{1}{2\sqrt{2}} \]
Thus, the correct answer is \( \frac{1}{2 \sqrt{2}} \).
If a random variable X has the following probability distribution values:
X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
---|---|---|---|---|---|---|---|---|
P(X) | 1/12 | 1/12 | 1/12 | 1/12 | 1/12 | 1/12 | 1/12 | 1/12 |
Then P(X ≥ 6) has the value: