Molarity (\( M \)) is calculated as:
\[ M = \frac{\text{moles of solute}}{\text{liters of solution}} \]
As temperature increases, the volume of the solution expands, leading to a decrease in molarity.
Weight % (A) and Mole fraction (B): These are independent of solution volume and are not significantly affected by temperature changes.
Molality (D): Defined per kg of solvent, molality remains unaffected by temperature changes.
Since molarity is volume-dependent, the correct answer is: (C) Molarity