The binding energy per nucleon is generally higher for heavier nuclei than for light nuclei. This is because light nuclei like hydrogen or helium have lower binding energies per nucleon compared to heavier nuclei like iron or uranium. As the mass number increases, the binding energy per nucleon also increases, reaching a maximum at iron (Fe). For light nuclei, the average binding energy per nucleon is relatively lower. Thus, the incorrect statement is that the average binding energy per nucleon is very high for light nuclei.
The correct option is (B) : Average binding energy per nucleon is very high for light nuclei.
Let's analyze each statement:
✔ Nuclear density is independent of the mass number A: This is correct, since density ≈ constant for all nuclei.
❌ Average binding energy per nucleon is very high for light nuclei: This is incorrect. Light nuclei like hydrogen, helium have lower binding energy per nucleon. It becomes maximum for medium mass nuclei like iron (Fe).
✔ Nuclear forces are the strongest in nature: Correct – Strong nuclear force is stronger than all other fundamental forces.
✔ Half-life is directly proportional to mean life: Correct – The relation is:
Mean life = 1.44 × Half-life
✔ Becquerel (Bq) is the SI unit of activity: Correct
✅ Correct Answer (INCORRECT Statement): Average binding energy per nucleon is very high for light nuclei.
Match the LIST-I with LIST-II
LIST-I (Type of decay in Radioactivity) | LIST-II (Reason for stability) | ||
---|---|---|---|
A. | Alpha decay | III. | Nucleus is mostly heavier than Pb (Z=82) |
B. | Beta negative decay | IV. | Nucleus has too many neutrons relative to the number of protons |
C. | Gamma decay | I. | Nucleus has excess energy in an excited state |
D. | Positron Emission | II. | Nucleus has too many protons relative to the number of neutrons |
Choose the correct answer from the options given below:
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): The density of the copper ($^{64}Cu$) nucleus is greater than that of the carbon ($^{12}C$) nucleus.
Reason (R): The nucleus of mass number A has a radius proportional to $A^{1/3}$.
In the light of the above statements, choose the most appropriate answer from the options given below: