Question

The hydrolysis products of \(\mathrm{ICl}\), \(\mathrm{ClF_3}\), and \(\mathrm{BrF_5}\) are respectively:

• A. HIO, HClO\(_3\), and HBrO\(_3\)
• B. HIO, HClO\(_2\), and HBrO\(_3\)
• C. HCl, HF, and HBrO\(_3\)
• D. HClO, HClO\(_3\), and HBrO\(_3\)

Hint:

Interhalogen compounds on hydrolysis often yield oxyacids of the more electronegative halogen. Recognize oxidation states for correct products.

Answer 1

The Correct Option is A

Let us consider the hydrolysis reactions of the given interhalogen compounds: 1. ICl (Iodine monochloride): On hydrolysis: \[ \mathrm{ICl + H_2O \rightarrow HIO + HCl} \] Thus, it forms hypoiodous acid (HIO) — a weak monobasic acid. 2. ClF\(_3\) (Chlorine trifluoride): On hydrolysis: \[ \mathrm{ClF_3 + 3H_2O \rightarrow HClO_3 + 3HF} \] Here, \(\mathrm{HClO_3}\) is chloric acid (oxidation state of Cl = +5). 3. BrF\(_5\) (Bromine pentafluoride): On hydrolysis: \[ \mathrm{BrF_5 + 3H_2O \rightarrow HBrO_3 + 5HF} \] Here, \(\mathrm{HBrO_3}\) is bromic acid (oxidation state of Br = +5). Therefore, the correct set of hydrolysis products is: HIO, HClO\(_3\), and HBrO\(_3\)