The hybridization and number of lone pair of electrons on central atom of SF$_4$ respectively are
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- sp$^3$d, 1
- sp$^3$d$^2$, 2
- dsp$^2$, 0
- sp$^3$, 0
The Correct Option is A
Solution and Explanation
- Sulfur has 6 valence electrons.
- 4 electrons are used in bonding with 4 fluorine atoms.
- 1 lone pair remains.
Steric number = 4 bond pairs + 1 lone pair = 5 ⇒ hybridization = sp$^3$d
So, hybridization = sp$^3$d and lone pairs = 1
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