Question:
The Henry’s law constant (KH) values of three gases (A, B, C) in water are 145, 2 × 10–5 and 35 kbar, respectively. The solubility of these gases in water follow the order :
The Henry’s law constant (KH) values of three gases (A, B, C) in water are 145, 2 × 10–5 and 35 kbar, respectively. The solubility of these gases in water follow the order :
Updated On: Dec 4, 2024
- B > A > C
- B > C > A
- A > C > B
- A > B > C
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The Correct Option is B
Solution and Explanation
1. Solubility is inversely proportional to $K_H$. Lower $K_H$ implies higher solubility.
2. $K_H$ values: A = 145, B = $2 \times 10^{-5}$, C = 35.
3. Order of solubility: B (lowest $K_H$) > C > A.
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