Step 1: Formula for Curved Surface Area of Cylinder.
The formula for the curved surface area (C.S.A) of a cylinder is:
\[
\text{C.S.A} = 2 \pi r h
\]
where \( r \) is the radius and \( h \) is the height.
Given that C.S.A = 264 cm\(^2\) and \( h = 14 \) cm, we substitute the values into the formula:
\[
264 = 2 \times \frac{22}{7} \times r \times 14
\]
Simplifying:
\[
264 = \frac{22}{7} \times 28 \times r \implies r = \frac{264 \times 7}{22 \times 28} = \frac{1848}{616} = 3
\]
Thus, the radius \( r = 3 \) cm.
Step 2: Formula for Volume of Cylinder.
The volume \( V \) of the cylinder is given by:
\[
V = \pi r^2 h
\]
Substituting \( r = 3 \) cm and \( h = 14 \) cm:
\[
V = \frac{22}{7} \times 3^2 \times 14 = \frac{22}{7} \times 9 \times 14 = 396 \, \text{cm}^3
\]
Final Answer: \[ \boxed{396 \, \text{cm}^3} \]
A weight of $500\,$N is held on a smooth plane inclined at $30^\circ$ to the horizontal by a force $P$ acting at $30^\circ$ to the inclined plane as shown. Then the value of force $P$ is:
A steel wire of $20$ mm diameter is bent into a circular shape of $10$ m radius. If modulus of elasticity of wire is $2\times10^{5}\ \text{N/mm}^2$, then the maximum bending stress induced in wire is: