Step 1: Understanding the Shape of the Model.
The model consists of two cones and a cylindrical part. The diameter of the model is 3 cm, which gives the radius \( r = \frac{3}{2} = 1.5 \) cm. The total height of the model is 12 cm, which is the combined height of the two cones and the cylinder.
The height of each cone is 2 cm.
The remaining height is the height of the cylinder. Since the total height is 12 cm and the two cones have a combined height of \( 2 \times 2 = 4 \) cm, the height of the cylinder is \( 12 - 4 = 8 \) cm.
Step 2: Volume of a Cone.
The volume \( V \) of a cone is given by the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
For each cone, \( r = 1.5 \, \text{cm} \) and \( h = 2 \, \text{cm} \). So, the volume of one cone is:
\[
V_{\text{cone}} = \frac{1}{3} \times \frac{22}{7} \times (1.5)^2 \times 2
\]
\[
V_{\text{cone}} = \frac{1}{3} \times \frac{22}{7} \times 2.25 \times 2 = \frac{1}{3} \times \frac{22}{7} \times 4.5
\]
\[
V_{\text{cone}} = \frac{1}{3} \times \frac{99}{7} = \frac{33}{7} = 4.71 \, \text{cm}^3
\]
The total volume of the two cones is:
\[
V_{\text{cones}} = 2 \times 4.71 = 9.42 \, \text{cm}^3
\]
Step 3: Volume of the Cylinder.
The volume \( V \) of a cylinder is given by the formula:
\[
V = \pi r^2 h
\]
For the cylinder, \( r = 1.5 \, \text{cm} \) and \( h = 8 \, \text{cm} \). So, the volume of the cylinder is:
\[
V_{\text{cylinder}} = \frac{22}{7} \times (1.5)^2 \times 8
\]
\[
V_{\text{cylinder}} = \frac{22}{7} \times 2.25 \times 8 = \frac{22}{7} \times 18 = \frac{396}{7} = 56.57 \, \text{cm}^3
\]
Step 4: Total Volume of the Model.
The total volume of the model is the sum of the volumes of the two cones and the cylinder:
\[
V_{\text{total}} = V_{\text{cones}} + V_{\text{cylinder}} = 9.42 + 56.57 = 36 \, \text{cm}^3
\]
Step 5: Conclusion.
Thus, the total volume of the model is \( 36 \, \text{cm}^3 \).