Question:
The half life period of a radioactive substance is 60 days The time taken for $\frac{7}{8}$ th of its original mass to disintegrate will be :
The half life period of a radioactive substance is 60 days The time taken for $\frac{7}{8}$ th of its original mass to disintegrate will be :
Updated On: Mar 19, 2025
- 120 days
- 130 days
- 180 days
- 20 days
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
From the given options the correct answer is option (C): 180 days
Was this answer helpful?
0
0
Top Questions on Nuclear physics
Match the following types of nuclei with examples shown:
- KCET - 2025
- Physics
- Nuclear physics
- For a nucleus of mass number $ A $ and radius $ R $, the mass density of the nucleus can be represented as:
- JEE Main - 2025
- Physics
- Nuclear physics
- For a nucleus of mass number $A$ and radius $R$, mass density $\rho$. Then choose the correct option.
- JEE Main - 2025
- Physics
- Nuclear physics
- For a nucleus of mass number $ A $ and radius $ R $, mass density is $ \rho $. Then choose the correct option.
- JEE Main - 2025
- Physics
- Nuclear physics
- Given below are two statements. One is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A): The binding energy per nucleon is found to be practically independent of the atomic number \( A \), for nuclei with mass numbers between 30 and 170. Reason (R): Nuclear force is long range. In the light of the above statements, choose the correct answer from the options given below:
- JEE Main - 2025
- Physics
- Nuclear physics
View More Questions
Questions Asked in JEE Main exam
The remainder when \( 64^{64} \) is divided by 7 is equal to:
- JEE Main - 2025
- Arithmetic Progression
- The sum of the infinite series $ \cot^{-1} \left( \frac{7}{4} \right) + \cot^{-1} \left( \frac{19}{4} \right) + \cot^{-1} \left( \frac{39}{4} \right) + \cot^{-1} \left( \frac{67}{4} \right) + ... $ is:
- JEE Main - 2025
- Sequence and series
- If $ \alpha $ is a root of the equation $ x^2 + x + 1 = 0 $ and $$ \sum_{k=1}^{n} \left( \alpha^k + \frac{1}{\alpha^k} \right)^2 = 20$$, then n is equal to _______
- JEE Main - 2025
- Sequence and series
x mg of Mg(OH)$_2$ (molar mass = 58) is required to be dissolved in 1.0 L of water to produce a pH of 10.0 at 298 K. The value of x is ____ mg. (Nearest integer) (Given: Mg(OH)$_2$ is assumed to dissociate completely in H$_2$O)
- JEE Main - 2025
- Equilibrium
- The amount of calcium oxide produced on heating 150 kg limestone (75% pure) is _______ kg. (Nearest integer)
Given: Molar mass (in g mol$^{-1}$) of Ca-40, O-16, C-12- JEE Main - 2025
- Stoichiometry and Stoichiometric Calculations
View More Questions