Question:

The half-life of radioactive radon is 3.8 days. The time at the end of which \(\frac{1}{20}th\) of the Radon sample will remain undecayed is (given log10e=0.4343)

Updated On: Apr 19, 2024
  • 3.8 days
  • 16.5 days
  • 33 days
  • 76 days
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The Correct Option is B

Solution and Explanation

The correct option is B)
t\(_\frac{1}{2}\) =3.8 day
∴ λ = \(\frac{0.693}{t_\frac{1}{2}}\)=\( \frac{0.693}{3.8}\)= 0.182
If the initial number of atoms is a=A0​ then after time t the number of atoms is \(\frac{a}{20}\) = a
\(t=\frac{2.303}{\lambda}log\frac{A_0}{A}=\frac{2.303}{0.182}log\frac{a}{a/20}\)
\(=\frac{2.303}{0.182}log 20 = 16.46\)
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Concepts Used:

Nuclei

In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.

Read More: Nuclei

Following are the terms related to nucleus:

  1. Atomic Number
  2. Mass Number
  3. Nuclear Size
  4. Nuclear Density
  5. Atomic Mass Unit