Question:

The gravitational field strength at the surface of a certain planet is gg. Which of the following is the gravitational field strength at the surface of a planet with twice the radius and twice the mass?

Updated On: May 12, 2024
  • g/2g/2
  • gg
  • 2g2g
  • 4g4g
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The Correct Option is A

Solution and Explanation

For a given planet, g=GMR2g = \frac{GM}{R^2}
Gravitational field strength at the surface of another planet, g=GMR2g' = \frac{GM'}{R'^2}
Here, M=2M,R=2RM' = 2M , R' = 2R
   g=G(1M)(2R)2=g2\therefore \:\:\: g' = \frac{G(1M)}{(2R)^2} = \frac{g}{2}
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].