We begin with \((x + 2y)^3 \frac{dy}{dx} = y\). Rearranging: \(\frac{dy}{dx} = \frac{y}{(x + 2y)^3}\)
Use substitution \(x = yv\), so \(dx = vdy + ydv\). Then transform and simplify. The equation becomes separable.
Integration eventually gives: \(x = y^3 + cy\)