\(Pt(s) ∣ H2(g)(1atm) ∣ H+(aq, [H+]=1)\, ∥\, Fe3+(aq), Fe2+(aq) ∣ Pt(s)\)Given\( E^∘_{Fe^{3+}Fe^{2+}}\)\(=0.771V\) and \(E^∘_{H^{+1/2}H_2}=0\,V,T=298K\)If the potential of the cell is 0.712V, the ratio of concentration of \(Fe2+\) to \(Fe3+\) is