Question:
The function \[f(x,y) = \begin{cases} \frac{x^3-y^3}{x^2+y^2} ,when \space x≠0, y≠0.\\ k, when \space x = 0, y=0 \end{cases}\]is continuous at (0,0), then k is equal to:
The function
\[f(x,y) = \begin{cases} \frac{x^3-y^3}{x^2+y^2} ,when \space x≠0, y≠0.\\ k, when \space x = 0, y=0 \end{cases}\]is continuous at (0,0), then k is equal to:
Updated On: Dec 17, 2025
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The Correct Option is D
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The correct option is(D):0
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