Question:

The fringe width in interference of light due to two coherent sources is:

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Fringe width increases with wavelength in interference patterns.
  • proportional to wavelength
  • inversely proportional to wavelength
  • proportional to square of wavelength
  • inversely proportional to square of wavelength
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The Correct Option is A

Solution and Explanation

The fringe width \(\beta\) in interference is given by: \[ \beta = \frac{\lambda D}{d} \] where \(\lambda\) is the wavelength, \(D\) is the distance to the screen, and \(d\) is the distance between the sources. Hence, fringe width is directly proportional to the wavelength.
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