Question

The frequency of a photon of energy 1.326eV is:

• A. \(1.18 \times 10^{14}\,\text{Hz}\)
• B. \(3.20 \times 10^{14}\,\text{Hz}\)
• C. \(4.20 \times 10^{15}\,\text{Hz}\)
• D. \(4.80 \times 10^{15}\,\text{Hz}\)

Hint:

Convert eV to joules using \(1\,\text{eV} = 1.6 \times 10^{-19}\,\text{J}\), and use \( \nu = \frac{E}{h} \) to find frequency.

Answer 1

The Correct Option is B

We use the relation: \[ E = h \nu \Rightarrow \nu = \frac{E}{h} \] Given: \[ E = 1.326\,\text{eV} = 1.326 \times 1.6 \times 10^{-19}\,\text{J},\quad h = 6.63 \times 10^{-34}\,\text{J·s} \] \[ \nu = \frac{1.326 \times 1.6 \times 10^{-19}}{6.63 \times 10^{-34}} \approx 3.20 \times 10^{14}\,\text{Hz} \]