Question:

The formula of microcosmic salt and the product obtained by heating it is

Updated On: Jul 2, 2022
  • $Na \left( NH _{4}\right) PO _{4} ; NaPO _{3}$
  • $Na \left( NH _{4}\right)_{2} HPO _{4} ; NaPO _{3}$
  • $Na \left( NH _{4}\right) HPO _{4} ; NaPO _{4}$
  • $Na \left( NH _{4}\right) HPO _{4} ; NaPO _{3}$
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The Correct Option is D

Solution and Explanation

Microcosmic salt is Na(NH 4 )HPO. $ {Na(NH4 )HPO4 ->[?] NaPO3 + H2O + NH3}$ It is prepared by : $ {NH4Cl + Na2HPO 4 + 4H2O -> Na(NH4)HPO4. 4H2O + NaCl}$
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Concepts Used:

Group 1 Elements

Group one of alkali metals is s-block elements with just one electron in their s-orbital. They are are alkali metals. They are named so because of the alkaline nature of the hydroxides and oxides.

Alkali metals are characterized by one s-electron in the valence shell of their atoms.

Alkali metals have a corresponding [Noble gas] ns1 electronic configuration. They occupy the first column of the periodic table. Alkali elements are:

  • Lithium(Li)
  • Sodium(Na)
  • Potassium (K)
  • Rubidium (Ru)
  • Cesium (Cs)
  • Francium (Fr)

They have occupied successive periods from first to seven. Francium is a radioactive element with very low half-life.

Electronic Configuration:

  • Alkali metals have one electron in their valence shell.
  • The electronic configuration is given by ns1. For example, the electronic configuration of lithium is given by 1ns1 2ns1.
  • They tend to lose the outer shell electron to form cations with charge +1 (monovalent ions).

This makes them the most electropositive elements and due to the same reason, they are not found in the pure state.