Question:
The force between two conducting spheres of same radius having charges +8 μC and -4 μC separated by some distance in air is F. If the spheres are connected by a conducting wire and after some time the wire is removed, then the magnitude of the force between the two conducting spheres is
The force between two conducting spheres of same radius having charges +8 μC and -4 μC separated by some distance in air is F. If the spheres are connected by a conducting wire and after some time the wire is removed, then the magnitude of the force between the two conducting spheres is
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Remember that when charges are redistributed, the new force depends on the square of the charges involved.
Updated On: Jun 6, 2025
- $F$
- $\frac{F}{2}$
- $8F$
- $\frac{F}{4}$
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The Correct Option is C
Solution and Explanation
When the spheres are connected by a conducting wire, the charges redistribute equally. The new charge on each sphere becomes $\frac{+8 \, \mu C + (-4 \, \mu C)}{2} = 2 \, \mu C$. Using Coulomb's law for the force between two charges, the force is proportional to the square of the charge. Hence, the new force will be $8F$.
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