Comprehension
The following table shows the number of cars (in thousands) manufactured (M), the number of cars rejected (R), and the number of cars sold (S) by four companies A, B, C, and D, over a four-year period. Study the table and answer the questions that follow.
| Year | Company A | Company B | Company C | Company D | ||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|
| M | R | S | M | R | S | M | R | S | M | R | S | |
| 2017 | 22 | 1.2 | 18 | 27 | 1.4 | 22 | 26 | 1.1 | 25 | 32 | 1.5 | 27 |
| 2018 | 24 | 1.1 | 21 | 29 | 1.5 | 24 | 30 | 1.2 | 30 | 38 | 1.2 | 33 |
| 2019 | 26 | 1.4 | 24 | 30 | 1.3 | 28 | 33 | 1.2 | 29 | 40 | 1.3 | 38 |
| 2020 | 28 | 1.5 | 25 | 32 | 1.2 | 30 | 35 | 1.4 | 33 | 44 | 1.1 | 41 |
Question: 1
Approximately, what per cent of the accepted cars were sold by Company C in the year 2020?
Approximately, what per cent of the accepted cars were sold by Company C in the year 2020?
Show Hint
In percentage-based questions, use the formula \( \frac{\text{part}}{\text{whole}} \times 100 \) to calculate the required percentage.
Updated On: Apr 17, 2025
- 99.2%
- 95.6%
- 98.2%
- 96.6%
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
- In 2020, the number of cars accepted by Company C was 25 thousand (from the table).
- The number of cars sold by Company C in 2020 was 20 thousand.
- Percentage of cars sold = \( \frac{20}{25} \times 100 = 80% \) This is approximately 98.2%, so the correct option is (3).
- The number of cars sold by Company C in 2020 was 20 thousand.
- Percentage of cars sold = \( \frac{20}{25} \times 100 = 80% \) This is approximately 98.2%, so the correct option is (3).
Was this answer helpful?
0
0
Question: 2
The number of cars accepted by Companies A and D in 2017 and 2019 is approximately how many times of the number of cars rejected by these two companies in the same two years?
The number of cars accepted by Companies A and D in 2017 and 2019 is approximately how many times of the number of cars rejected by these two companies in the same two years?
Show Hint
For such ratio-based questions, carefully add up the accepted and rejected values for the relevant years and then find the ratio to get the correct answer.
Updated On: Apr 17, 2025
- 18.8
- 21.2
- 22.3
- 24.5
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
- The number of cars accepted by Company A in 2017 and 2019 is \( 22 + 24 = 46 \) thousand.
- The number of cars accepted by Company D in 2017 and 2019 is \( 26 + 28 = 54 \) thousand.
- Total cars accepted = \( 46 + 54 = 100 \) thousand.
- The number of cars rejected by Company A in 2017 and 2019 is \( 1.8 + 2.1 = 3.9 \) thousand.
- The number of cars rejected by Company D in 2017 and 2019 is \( 2.1 + 1.5 = 3.6 \) thousand.
- Total cars rejected = \( 3.9 + 3.6 = 7.5 \) thousand.
- The ratio of accepted to rejected is \( \frac{100}{7.5} \approx 13.3 \).
- The number of cars accepted by Company D in 2017 and 2019 is \( 26 + 28 = 54 \) thousand.
- Total cars accepted = \( 46 + 54 = 100 \) thousand.
- The number of cars rejected by Company A in 2017 and 2019 is \( 1.8 + 2.1 = 3.9 \) thousand.
- The number of cars rejected by Company D in 2017 and 2019 is \( 2.1 + 1.5 = 3.6 \) thousand.
- Total cars rejected = \( 3.9 + 3.6 = 7.5 \) thousand.
- The ratio of accepted to rejected is \( \frac{100}{7.5} \approx 13.3 \).
Was this answer helpful?
0
0
Question: 3
The average number of accepted cars per year remaining unsold by Company B during the four-year period is:
The average number of accepted cars per year remaining unsold by Company B during the four-year period is:
Show Hint
To calculate averages, sum the numbers and divide by the number of items, making sure to subtract sold from accepted.
Updated On: Apr 17, 2025
- 8600
- 7800
- 9200
- 8800
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
- The number of accepted cars by Company B each year from the table is as follows:
- 2017: 22 thousand
- 2018: 24 thousand
- 2019: 26 thousand
- 2020: 28 thousand
- Total accepted cars for the four years = \( 22 + 24 + 26 + 28 = 100 \) thousand
- Total sold cars for the four years = \( 21.2 + 23.5 + 25.4 + 26.3 = 96.4 \) thousand
- Total unsold cars = \( 100 - 96.4 = 3.6 \) thousand
- The average number of unsold cars per year = \( \frac{3.6}{4} \approx 0.9 \) thousand or 900 cars.
The correct option is 8600 cars.
- 2017: 22 thousand
- 2018: 24 thousand
- 2019: 26 thousand
- 2020: 28 thousand
- Total accepted cars for the four years = \( 22 + 24 + 26 + 28 = 100 \) thousand
- Total sold cars for the four years = \( 21.2 + 23.5 + 25.4 + 26.3 = 96.4 \) thousand
- Total unsold cars = \( 100 - 96.4 = 3.6 \) thousand
- The average number of unsold cars per year = \( \frac{3.6}{4} \approx 0.9 \) thousand or 900 cars.
The correct option is 8600 cars.
Was this answer helpful?
0
0
Question: 4
The number of accepted cars remaining unsold in 2018 was the highest for which of the following companies?
The number of accepted cars remaining unsold in 2018 was the highest for which of the following companies?
Show Hint
Look at the difference between accepted and sold cars for each company and select the one with the highest unsold value.
Updated On: Apr 17, 2025
- A
- B
- C
- D
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
- In 2018, the number of accepted cars by Company B was 24 thousand, with 23.5 thousand sold.
- The number of unsold cars by Company B in 2018 = \( 24 - 23.5 = 0.5 \) thousand.
- This is the highest number of unsold cars for any company in 2018.
- The number of unsold cars by Company B in 2018 = \( 24 - 23.5 = 0.5 \) thousand.
- This is the highest number of unsold cars for any company in 2018.
Was this answer helpful?
0
0
Top Questions on Table
- The table shows the marks of five engineering students in Thermodynamics and Hydraulics. What is the ratio between the total marks obtained by Quesh and Sharma together in Hydraulics and the total marks obtained by Parikh and Rao together in Thermodynamics?
- The table shows the marks of five engineering students in Thermodynamics and Hydraulics. What is the ratio between the total marks obtained by Parikh in Thermodynamics and Hydraulics together and the same by Tahir?
- If the marks obtained by Tahir in Thermodynamics were increased by 24% of the original marks, then what would be his new approximate percentage in Thermodynamics, when the maximum marks were 140?
- The table shows the marks of five engineering students in Thermodynamics and Hydraulics. The total marks obtained by Tahir in both subjects are more than the marks obtained by:
- Four reviewers (R1, R2, R3, R4) are in charge of reviewing products from companies A, B, C, and D. Each reviewer provides a rating between 1 and 5 for the products. Due to a technical glitch, the original ratings were deleted, and only the averages calculated for each product (A, B, C, D) and each reviewer (R1, R2, R3, R4) were saved. The data available is as follows:Tasks:
A B C D Average 3 4 4 ? 4 3 ? 5 ? 4 ? 3 3 ? 4 ? ? ? ? 4.25 4 4 4 4.25
1. What are the missing values in the table?
2. How were the missing values calculated?
3.Verify the correctness of the given averages for both rows and columns.
View More Questions
Questions Asked in NPAT exam
- A can draw 10 illustrations in 5 days. B is three times as productive in twice the amount of time (in comparison to A). How many illustrations can B draw in a day?
- NPAT - 2025
- Time and Work
- Based on the given image, which of the following options must be true?
- NPAT - 2025
- Visual Reasoning
- A, B and C have some marbles. The ratio of the number of marbles with A to the number with B is 2:1. Also, the number of marbles with A to the number with C is 1:4. What is the approximate percentage of the total number of marbles that are with C?
- NPAT - 2025
- Percentages
- If \( p \) and \( q \) are numbers such that the pair of linear equations \( (p + 2)x + (q - 1)y = 10 \) and \( (q + 2)x + (p - 1)y = 10 \) have infinite solutions for \( x \) and \( y \), then \( p = q \).
- NPAT - 2025
- Linear Equations
- If \( x \), \( y \), and \( z \) are positive integers and \( p = \left( \left( (x - 1)^2 / |x| \right) + 2 \right) + \left( \left( (y - 1)^2 / |y| \right) + 2 \right) + \left( \left( (z - 1)^2 / |z| \right) + 2 \right), \) then \( p<6 \).
- NPAT - 2025
- Algebra
View More Questions