Question:

The first-order partial derivative of the function \( \log(\sin x + \cos y) \) with respect to the variables \( x \) and \( y \), respectively, are given by:

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Apply the chain rule carefully for logarithmic functions involving multiple variables.
Updated On: Dec 28, 2024
  • \( \frac{\cos x}{\sin x + \cos y}, \frac{-\sin y}{\sin x + \cos y} \)
  • \( \frac{\sin x}{\sin x + \cos y}, \frac{\cos y}{\sin x + \cos y} \)
  • \( \frac{-\cos x}{\sin x + \cos y}, \frac{-\sin y}{\sin x + \cos y} \)
  • \( \frac{\cos x}{\sin x + \cos y}, \frac{\sin y}{\sin x + \cos y} \)
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The Correct Option is A

Solution and Explanation

Using partial differentiation:

\( \frac{\partial}{\partial x} \log(\sin x + \cos y) = \frac{\cos x}{\sin x + \cos y}, \quad \frac{\partial}{\partial y} \log(\sin x + \cos y) = \frac{-\sin y}{\sin x + \cos y}. \)

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