Question:

The first ionisation potential (in eV) of Be and B, respectively are

Updated On: Aug 1, 2024
  • 8.29, 9.32
  • 9.32, 9.32
  • 8.29, 8.29
  • 9.32, 8.29
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The Correct Option is D

Solution and Explanation

First ionisation potential of Be is greater than
boron due to stable configuration
$ \, \, \, \, \, \, \, \, \, \, _4 Be =1s^2 , 2s^2$
$ \, \, \, \, \, \, \, \, \, \, _5 B=1s^2,2s^2 2p^1$
Order of attraction of electrons towards nucleus is 2s >2p, so more amount of energy is required to remove the electron from 2 s orbital in comparison to 2p orbital. So, ionisation potential of Be is 9.32 eV and B is 8.29 eV
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Concepts Used:

Haloalkanes and Haloarenes - Classification

Classification of Haloalkanes and Haloarenes are as follows:

Haloalkanes and Haloarenes are Classified on the Basis of the Number of Halogen Atoms:

These are further classified as mono, di, or polyhalogen (tri-,tetra-, etc.) compounds depending on whether they contain one, two or more halogen atoms in their structures. For example;

  • Monohaloalkane
  • Dihaloalkane
  • Trihaloalkane

Haloalkanes and Haloarenes are Classified on Compounds Containing sp3 C—X Bond (X= F, Cl, Br, I)

This class includes:

  • Alkyl halides or haloalkanes (R—X)
  • Allylic halides
  • Benzylic halides

Haloalkanes and Haloarenes are Classified on Compounds Containing sp2 C—X Bond

This class includes:

  • Vinylic halides
  • Aryl halides